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125^x=(1/25)^x-3
We move all terms to the left:
125^x-((1/25)^x-3)=0
Domain of the equation: 25)^x-3)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
125^x-((+1/25)^x-3)=0
We multiply all the terms by the denominator
125^x*25)^x-3)-((+1=0
Wy multiply elements
3125x^2+1=0
a = 3125; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·3125·1
Δ = -12500
Delta is less than zero, so there is no solution for the equation
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